Question

Whisky obtained from fermented cereals contain 46% w/w
alcohol (ethanol). 100 gm whisky react with 12 and KOH to
produce CHI3. Find the number of moles of 12 required to
react all the alcohol present in above amount of whisky.​

Answer 1

Answer:

A part of this whisky is replaced by another containing 19% alcohols and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced of whisky replaced is : A. 1/3 ... 1000 p, (100 x)p. (100x - 1000)p, 70 p ... From this container 4 litres of milk was taken out and replaced by water.

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Explanation:

Answer 2

2.25 moles of iodine are required to react with all the ethanol present in 100 g of whisky.

The given problem involves the reaction of ethanol present in whisky with iodine and potassium hydroxide to produce iodoform (CHI3). The balanced equation for the reaction is given below:

4 CH3CH2OH + 9 I2 + 6 KOH → 4 CHI3 + 6 KI + 6 H2O

• From the balanced equation, we can see that 4 moles of ethanol react with 9 moles of iodine to produce 4 moles of iodoform. Therefore, the molar ratio of ethanol to iodine in this reaction is 4:9.
• To find the number of moles of iodine required to react with all the ethanol present in 100 g of whisky, we need to first calculate the amount (in moles) of ethanol present in 100 g of whisky.
• Assuming the density of whisky is 0.8 g/mL, we can calculate the volume of 100 g of whisky as:
  

Volume = Mass / Density = 100 g / 0.8 g/mL = 125 mL

• Since the whisky contains 46% w/w ethanol, the mass of ethanol present in 100 g of whisky can be calculated as:
  

Mass of ethanol = 46% of 100 g = 0.46 x 100 g = 46 g

• The molar mass of ethanol is 46 g/mole, so the number of moles of ethanol present in 46 g of ethanol is:
  

Number of moles of ethanol = Mass of ethanol / Molar mass of ethanol

= 46 g / 46 g/mole = 1 mole

• Therefore, the number of moles of ethanol present in 100 g of whisky is also 1 mole.
• Using the molar ratio of ethanol to iodine from the balanced equation, we can calculate the number of moles of iodine required to react with 1 mole of ethanol:
  

4 moles of ethanol : 9 moles of iodine

1 mole of ethanol : (9/4) moles of iodine

• Therefore, the number of moles of iodine required to react with 1 mole of ethanol is (9/4) moles.
• To react with 1 mole of ethanol present in 100 g of whisky, we need (9/4) moles of iodine. Therefore, the number of moles of iodine required to react with all the ethanol present in 100 g of whisky can be calculated as:
• Number of moles of iodine = (9/4) moles x 1 mole = 2.25 moles

So, 2.25 moles of iodine are required to react with all the ethanol present in 100 g of whisky.

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