Question

white headed thrush​

Answer 1

Answer:

Solution :-

\frac{2}{5} {x}^{2} - x + \frac{3}{5} = 0

5

2

x

2

−x+

5

3

=0

Now multiply by 5 in every term

\begin{lgathered}5 \times \frac{2}{5} {x}^{2} - 5x + 5 \times \frac{3}{5} = 5 \times 0 \\ \\ 2 {x}^{2} - 5x + 3 = 0\end{lgathered}

5×

5

2

x

2

−5x+5×

5

3

=5×0

2x

2

−5x+3=0

Now Factorise by splitting middle term

\begin{lgathered}2 {x}^{2} - 2x - 3x + 3 = 0 \\ \\ 2x(x - 1) - 3(x - 1) = 0 \\ \\ (x - 1)(2x - 3) = 0\end{lgathered}

2x

2

−2x−3x+3=0

2x(x−1)−3(x−1)=0

(x−1)(2x−3)=0

Now split it into possible cases

\begin{lgathered}(x - 1) = 0 \\ \\ (2x - 3) = 0\end{lgathered}

(x−1)=0

(2x−3)=0

Hence,

\begin{lgathered}x_1 = 1 \\ \\ x_2 =( \frac{3}{2} )\end{lgathered}

x

1

=1

x

2

=(

2

3

)

Extra information :-

A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.