Whitout actually calculating the cubes ,find the the value of (-12)cube+7cube+5cube
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Answered by
1
(-12)3 + (7)3 + (5)3
Let x = -12, y = 7 and z = 5
We observed that, x + y + z = -12 + 7 + 5 = 0
We know that if,
x + y + z = 0, then x3 + y3 + z3 = 3xyz
(-12)3 + (7)3 + (5)3 = 3(-12)(7)(5) = -1260
Let x = -12, y = 7 and z = 5
We observed that, x + y + z = -12 + 7 + 5 = 0
We know that if,
x + y + z = 0, then x3 + y3 + z3 = 3xyz
(-12)3 + (7)3 + (5)3 = 3(-12)(7)(5) = -1260
Answered by
0
If x+y+z=0
then x^3+y^3+z^3=3xyz
so,-12+7+5
=-12+12=0
-12^3+7^3+5^3=3(-12)(7)(5)
= -12^3+7^3+5^3=-36*35= -1260
then x^3+y^3+z^3=3xyz
so,-12+7+5
=-12+12=0
-12^3+7^3+5^3=3(-12)(7)(5)
= -12^3+7^3+5^3=-36*35= -1260
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