WHIUSC p o 40.
5. Calculate the emf of the cell in which the following reaction takes place:
Ni(s) + 2Ag (0.002 M) Ni2+ (0.160 M) + 2Ag(s)
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Answered by
6
Answer:
Explanation:
Applying Nernst equation we have:
see attachment
= 1.05 - 0.02955 log 4 × 104
= 1.05 - 0.02955 (log 10000 + log 4)
= 1.05 - 0.02955 (4 + 0.6021)
= 0.914 V
Attachments:
Answered by
6
Answer:
IN THE ATTACHMENT GIVEN ABOVE
Attachments:
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