Question

Who am I?
I am a 3-digit odd number,
2 lam a multiple of five,
3 My ones digit is a prime number,
@ Difference of tens and hundreds digit
is two more than ones digit,
3 Sum of my digits is a square number,
6 My tens digit is smaller than ones digit,
I am .........
​

Answer 1

Answer:

925

Step-by-step explanation:

Let the number be: 100a + 10b + c

Number is divisible by 5 hence units digit must be 0 or 5, but the units digits is a prime number, hence c=5

Difference of tens and hundreds digit is 2 more than ones digit.

Numerically: a-b=c+2

⇒a-b=7

Sum of digits is a square number ⇒ S = a+b+c = 9 or 16 (25 is not possible considering that c=5)

S≠9 as in that case a-b cannot be 7 ⇒ S=16 ⇒ a+b = 11

Hence |a-b|=7 and a+b = 11

⇒ a and b must be 9 and 2

The tens digit is smaller than 5(ones digit), hence b=2 and a=9

Hence the number is 100*9 + 10*2 + 5 = 925