who answer it correctly will be marked as brainliest...and followed by me
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It's 4 ampere...pls mark
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both side last 2 "5" in series
R'1= 5+5=10 , R'2 = 5+5 = 10
= inner side both R in series
R'3 = 5+5 = 10 , R'4= 5+5 = 10
=> R'1 & R'3 are in parallel also, R'2 & R'4 also in parallel
=> R"1 = R'1*R'3/(R'1+R'3) = 10*10(10+10) = 5
=> R"2 = R'2*R'4/(R'2+R'4) = 10*10/(10+10) = 5
=> R"1 & R"2 in parallel
=> R = R"1*R"2/(R"1+R"2) = 5*5/(5+5) = 25/10 = 2.5 ohm
=> V=IR
=> I = V/R
=> I = 10/2.5
=> I = 4 A
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