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a ball of mass 1 kg is dropped from a height of 7 m rebounds to a height of 4.5m. Calculate: its initial rebound velocity and kinetic energy.
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the formula P.E.=mgh=1x10x7=70J
K.E.=P.E=70j
KE= 1/2mv²
70=1/2×1×v²
v=11.8m/s
K.E.=P.E=70j
KE= 1/2mv²
70=1/2×1×v²
v=11.8m/s
Ramjipandey:
and also included this question. the loss of kinetic energy
will be what
please give answer
Loss in kinetic energy
=mg(h1-h2)
1×10(7-4.5)=25J
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