Question

who can give the answer of this question​

Answer 1

Answer:

but whaaat we have to find here ???

Answer 2

In ∆RSV;

height (h) = 10 cm

base (b) = 8 cm

$area = \frac{1}{2} \times b \times h \\ area = \frac{1}{2} \times 8 \times 10 = 4 \times 10 \\ area = 40 \: {cm}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: ... \: (i)$

quadrilateral STUV is a trapezium since SV || UT

In STUV;

height (h) = 17 - 10 = 7 cm

parallel sides, SV = 8 cm, UT = 14 cm

$area = \frac{1}{2} (sum \: of \: parallel \: sides)h \\ area = \frac{1}{2} (8 + 14)(7) = \frac{1}{2} \times 22 \times 7 = 11 \times 7 \\ area = 77 \: {cm}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: ... \: (ii)$

now, area of the given figure

= (i) + (ii)

= 40 + 77

= 117 cm²

Hence, area of the given figure is 117 cm².