Question

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Answer 1

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Q9) In Triangle ∆PSR and ∆PQR

/_SPR = /_PRQ (Alternate interior angle)
PR = PR (Common)
/_RPQ = /_SRP

Hence .. ∆PSR is Congruent to ∆PQR

Therefore By (C.P.C.T)
(i) PQ= RS
(ii) PS= QR
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Q10.) /_ XYZ=/_ XPZ (90°)
XZ = XZ ( Common)
XY = XP ( Given)
Hence . . ∆XYZ is congruent To ∆XPZ.

Hence All 3 Options Proved.

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