Question

who can solve this???​

Answer 1

Step-by-step explanation:

We have,

$\frac{ log_{a}(m) }{ log_{ab}(m) } = log_{a}(m) . log_{m}(ab)$

$= \frac{ log(m) }{ log(a) } . \frac{ log(a) + log(b) }{ log(m) } = \frac{ log(a) + log(b) }{ log(a) }$

$= 1 + log_{a}(b)$