Question

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Calculate the volume occupied by 11.2 g of the gas at NTP. Given that the vapour density of a gas is 11.2.???​

Answer 1

Answer:

11.2L

Explanation:

Molecular mass =2*vapour density

=2*11.2

=22.4

22.4g of gas = 1 mole of gas

11.2g of gas =1*11.2 /22.4

=0.5 mole

1 mole of gas =22.4 L of gas

0.5 mole of gas =22.4*0.5

=11.2L

Answer 2

Hey there !!

Mol mass=2 x vapour d

=2 x 11.2

=22.4 g

At NTP,

vol occupied by 22.4 g of gas= 22.4 L

vol of 11.2g gas = 22.4/22.4 x 11.2

= 11.2 L

Hope this will help you