Math, asked by mishranitya069, 10 months ago

who can solve this problem​

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Answered by Nitish321
1

 {a}^{2}  +  {b}^{2}  = 69 \\  {a}^{4}  +  {b}^{4}  = 3904 \\ or { {(a }^{2} +  {b}^{2} ) }^{2}   - 2 {a}^{2}  {b}^{2}  = 3409 \\ or \:  {(69)}^{2}  -  2{a}^{2}  {b}^{2}  = 3409 \\ or \:   {a}^{2}  {b}^{2}  =  \frac{1352}{2}  \\ or \: ab = 26 \\  \\ now  \:  {a}^{2}  +  {b}^{2}  =  {(a + b)}^{2} - 2ab \\ or \: 69 =  {(a + b)}^{2}  - 2 \times 26 \\ or \: (a + b ) = 11 \\  \\ so \:  {a}^{3}  +  {b}^{3}  =  {(a + b)}^{3}  - 3ab(a + b) \\  \:  \:  \:  \:  =  {(11)}^{3}  - 3 \times 26(11) \\  = 1331 - 858 \\  = 473

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