Question

Who can solve this question I am challenge any one​

Answer 1

Answer:

a) HCF :-

3y³ = 3 * y * y * y

15 y^5 = 3* 5 * y*y*y*y*y

Common = 3y³

HCF = 3y³

b) 4xy² = 2 * 2* x * y * y

16x²y = 2*2*2*2*x*x*y

common = 2*2*x*y

HCF = 4xy

Answer 2

1.3y³

2. 4xy

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