Question

Who can write all the questions and send me to Brainley? He is a Brainley Master. can do this all questions ​

Answer 1

Answer:

$\huge\underline\mathfrak{ANSWER}$

$\underline\mathfrak\red{question}$

1. Find the sum by suitable rearrangement:

• (a) 837+208+363

• (b) 1962+453+1538+647

$\underline\mathfrak\blue{answer}$

(a) =(837+363)+208

= 1200+208

= 1408

(b) = (1962+453)+(1538+647)

= 3500+1100

= 4600

$\underline\mathfrak\red{question}$

2. find the product by suitable rearrangement

• (a) 2×1768×50
• (b) 4×166×25
• (c) 8×291×125
• (d) 625×279×16
• (e) 285×5×60
• (f) 124×40×8×25

$\underline\mathfrak\blue{answer}$

(a) 2×1768×50

= 100×1768

= 176800

(b) 4×166×25

= 8 × 125 × 291

= 1000 × 291

= 291000

(c) 8×291×125

= 8 × 125 × 291

= 1000 × 291

= 291000

(d) 625×279×16

= 625 × 16 × 279

= 10000 × 279

= 2790000

(e) 285×5×60

= 285 × 300

= 85500

(f) 124×40×8×25

= 125 × 8 × 40 × 25

= 1000 × 1000

= 1000000

$\underline\mathfrak\red{question}$

3. find the value of the following

• (a) 297×17+297×3
• (b) 54279×92+8×54279
• (c) 81265×169-81265×69
• (d) 3845×5×728+769×25×218

$\underline\mathfrak\blue{answer}$

(a) 297×17+297×3

= 297 × (17 + 3)

= 297 × 20

= 5940

(b) 54279×92+8×54279

= 54279 × (92 + 8)

= 54279 × 100

= 5427900

(c) 81265×169-81265×69

= 81265 × (169 – 69)

= 81265 × 100

= 8126500

(d) 3845×5×728+769×25×218

= 3845 × 5 × 782 + 769 × 5 × 5 × 218

= 3845 × 5 × 782 + 3845 × 5 × 218

= 3845 × 5 × (782 + 218)

= 19225 × 1000

= 19225000

$\underline\mathfrak\red{question}$

4. find the product using suitable properties.

• (a) 738×103
• (b) 854×102
• (c) 258×1008
• (d) 1005×168

$\underline\mathfrak\blue{answer}$

(a) 738×103

= 738 × (100 + 3)

= 738 × 100 + 738 × 3 (using distributive property)

= 73800 + 2214

= 76014

(b) 854×102

= 854 × (100 + 2)

= 854 × 100 + 854 × 2 (using distributive property)

= 85400 + 1708

= 87108

(c) 258×1008

= 258 × (1000 + 8)

= 258 × 1000 + 258 × 8 (using distributive property)

= 258000 + 2064

= 260064

(d) 1005×168

= (1000 + 5) × 168

= 1000 × 168 + 5 × 168 (using distributive property)

= 168000 + 840

= 168840

$\underline\mathfrak\red{question}$

5. A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs ₹ 44 per litre, how much did he spend in all on petrol?

$\underline\mathfrak\blue{answer}$

Petrol quantity filled on Monday = 40 litres

Petrol quantity filled on Tuesday = 50 litres

Total petrol quantity filled = (40 + 50) litre

Cost of petrol per litre = ₹ 44

Total money spent = 44 × (40 + 50)

= 44 × 90

= ₹ 3960

so, this is your answer.