Who derived the Quadratic Formula? Pls give me a meaningful answer.
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Answer:
René Descartes
At the end of the 16th Century the mathematical notation and symbolism was introduced by amateur-mathematician François Viète, in France. In 1637, when René Descartes published La Géométrie, modern Mathematics was born, and the quadratic formula has adopted the form we know today.
Step-by-step explanation:
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First we need to identify the values for a, b, and c (the coefficients). First step, make sure the equation is in the format from above,
a
x
2
+
b
x
+
c
=
0
ax
2
+bx+c=0a, x, squared, plus, b, x, plus, c, equals, 0:
x
2
+
4
x
−
21
=
0
x
2
+4x−21=0x, squared, plus, 4, x, minus, 21, equals, 0
a
aa is the coefficient in front of
x
2
x
2
x, squared, so here
a
=
1
a=1a, equals, 1 (note that
a
aa can’t equal
0
00 -- the
x
2
x
2
x, squared is what makes it a quadratic).
b
bb is the coefficient in front of the
x
xx, so here
b
=
4
b=4b, equals, 4.
c
cc is the constant, or the term without any
x
xx next to it, so here
c
=
−
21
c=−21c, equals, minus, 21.
Then we plug
a
aa,
b
bb, and
c
cc into the formula:
x
=
−
4
±
16
−
4
⋅
1
⋅
(
−
21
)
2
x=
2
−4±
16−4⋅1⋅(−21)
x, equals, start fraction, minus, 4, plus minus, square root of, 16, minus, 4, dot, 1, dot, left parenthesis, minus, 21, right parenthesis, end square root, divided by, 2, end fraction
solving this looks like:
x
=
−
4
±
100
2
=
−
4
±
10
2
=
−
2
±
5
x
=
2
−4±
100
=
2
−4±10
=−2±5
Therefore
x
=
3
x=3x, equals, 3 or
x
=
−
7
x=−7x, equals, minus, 7.
a
x
2
+
b
x
+
c
=
0
ax
2
+bx+c=0a, x, squared, plus, b, x, plus, c, equals, 0:
x
2
+
4
x
−
21
=
0
x
2
+4x−21=0x, squared, plus, 4, x, minus, 21, equals, 0
a
aa is the coefficient in front of
x
2
x
2
x, squared, so here
a
=
1
a=1a, equals, 1 (note that
a
aa can’t equal
0
00 -- the
x
2
x
2
x, squared is what makes it a quadratic).
b
bb is the coefficient in front of the
x
xx, so here
b
=
4
b=4b, equals, 4.
c
cc is the constant, or the term without any
x
xx next to it, so here
c
=
−
21
c=−21c, equals, minus, 21.
Then we plug
a
aa,
b
bb, and
c
cc into the formula:
x
=
−
4
±
16
−
4
⋅
1
⋅
(
−
21
)
2
x=
2
−4±
16−4⋅1⋅(−21)
x, equals, start fraction, minus, 4, plus minus, square root of, 16, minus, 4, dot, 1, dot, left parenthesis, minus, 21, right parenthesis, end square root, divided by, 2, end fraction
solving this looks like:
x
=
−
4
±
100
2
=
−
4
±
10
2
=
−
2
±
5
x
=
2
−4±
100
=
2
−4±10
=−2±5
Therefore
x
=
3
x=3x, equals, 3 or
x
=
−
7
x=−7x, equals, minus, 7.
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