Question

who ever answers this properly get thirty points!!!!
simlpify:-2/3 power2 -1/6 power3 divided by 5/6 power 2

Answer 1

x+3=y…(3)x+3=y…(3)

and (2)(2) takes the form:

(x+3)3+1/(x+3)3=y3+1/y3…(4)(x+3)3+1/(x+3)3=y3+1/y3…(4)

By (3)(3) , equation (1)(1) becomes:

(y−3)2+(y−3)=5=>y2−6y+9+(y−3)−5=0=>(y−3)2+(y−3)=5=>y2−6y+9+(y−3)−5=0=>

y2−5y+1=0...(5)y2−5y+1=0...(5)

Now, since by (5)(5) it is evident that yy cannot be zero, we take:

y2−5y+1=0=>y2+1=5y=>y+1/y=5...(6)y2−5y+1=0=>y2+1=5y=>y+1/y=5...(6