who ever asked the question " A TWO DIGIT NUMBER IS 4 TIMES SUM OF ITS DIGIT.THE NUMBER IS 3 TIMES PRODUCT OF THE DIGITS.FIND THE NUMBER?" please send the link to the question in the comments or answer. I have the answer to the question but it took time so I lost the question because the app refreshed. please send it..
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A two digit positive integer can be expressed as 10x+y, where x is the tens digit and y is the ones digit. For example, 37 = 3(10)+7.
So, 10x+y = 4(x+y) and 10x+y = 3xy
10x+y = 4x+4y
6x = 3y
y = 2x
Since y = 2x and 10x+y = 3xy, we have 10x+2x=3x(2x)
12x = 6x2 6x2-12x = 0
6x(x-2) = 0 x = 0 or x = 2
Since x can't be zero, x = 2
y = 2x = 4
The number is 24.
So, 10x+y = 4(x+y) and 10x+y = 3xy
10x+y = 4x+4y
6x = 3y
y = 2x
Since y = 2x and 10x+y = 3xy, we have 10x+2x=3x(2x)
12x = 6x2 6x2-12x = 0
6x(x-2) = 0 x = 0 or x = 2
Since x can't be zero, x = 2
y = 2x = 4
The number is 24.
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