who get oxidised and reduced in this
2H2S+O2 --> 2H2O+2S
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Answer:
2 H2S-II + O20 → 2 S0 + 2 H2O-II
This is an oxidation-reduction (redox) reaction:
2 S-II - 4 e- → 2 S0 (oxidation)
2 O0 + 4 e- → 2 O-II (reduction)
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