Question

who give the answer fast and correctly i did whatever u say . just give answer

Answer 1

heya..!!!!


Let D and E be the initial and final positions of the plane


the triangle ABD


tan60=BD/AB

=> √3 = 1500√3 / AB

=> AB = 1500

now,

IN ∆ACE

tan 30° = CE/AC

=> 1/√3 = CE/AC

=> 1/√3 = 1500√3/AC

=> AC = 4500


AC = BC + AB

=> 4500 = BC + 1500

=> BC = 4500 - 1500

=> BC = 3000m

the plan travels a distance of 3000m in 15 seconds.


Therefore,

speed of the plane =3000/15 = 200 m/s

=> 200×18/5km/s

=> 40 × 18km/a

=> 720km/s