Question

Who gives correct answer i will mark them as brianalist

Answer 1

Step-by-step explanation:

Let a be the sides of cube.

Total surface area of cube = 6a²

Volume of cube = a³

Given : Total surface area of a cube =

$32\dfrac{2}{3}\ m^3=\dfrac{98}{3}\ m^3$

$\Rightarrow\ 6a^2=\dfrac{98}{3}\\\\\Rightarrow\ a^2=\dfrac{98}{3\times6}=\dfrac{49}{9}=(\dfrac{7}{3})^2\\\\\Rightarrow\ a=\dfrac{7}{3}\ m$

Now volume of cube =

$(\dfrac{7}{3})^3=\dfrac{7^3}{3^3}=\dfrac{343}{27}\ m^3$

$12\dfrac{19}{27}\ m^3$

Hence, the volume of the cube is =

$12\dfrac{19}{27}\ m^3$

or

$\frac{343}{27}$

Note :- In the question, it is given that surface area of cube. Surface area can't be in m^3

Answer 2

Answer:

this picture has a answer ............