Question

who gives the answer they will get
100 points
if mass ratio of non-reacting mixture of O2 and N2 in a vessel is 2 : 7 , then the ratio of their molecules will be

(a) 1 : 2 (b) 3 : 5

(c) 2 : 7 (d) 1 : 4

who gives the answer they will get 100 points ​

Answer 1

Answer:

The ratio between the number of molecules will be 2:7.

option (c)

Explanation:The ratio between the number of molecules will be 2:7.

You know that the mixture contains oxygen and nitrogen in a 1:4 mass ratio. You can write this as

mO2mN2=14

The mass of the two gases can be expressed using their respective molar masses and the number of moles of each present in the mixture

m=number of moles molar mass

mO2=nO232.0 g/mol

mN2=nN228.0 g/mol

This means that the mass ratio that exists between the two gases can be written as

mO2mN2=nO232.0g/mol⋅28.0g/molnN2=nO2nN2=14

7⋅nO28⋅nN2=14⇒nO2nN2=828=27

One mole of any substance contains exactly 6.022⋅1023 atoms or molecules of that substance - this is known as Avogadro's number.

In order to have 1 mole of oxygen, you need to have 6.022⋅1023 molecules of oxygen. Likewise, 1 mole of nitrogen must contain 6.022⋅1023 molecules of nitrogen.

So, if your gaseous mixture contains oxygen and nitrogen in a 2:7 mole ratio, then the ratio between the number of molecules of each gas must be equal to 2:7 as well.

Regardless of how many moles of oxygen you actually have, the 2:7 ratio you have between the two gases applies to the number of molecules too.

For example, if you have 0.5 moles of oxygen and 1.75 moles of nitrogen, you'd get

0.5molesO2⋅6.022⋅1023molecules1moleO2=3.011⋅1023moleculesO2

and

1.75molesN2⋅6.022⋅1023moleculesN21moleN2=10.5385⋅1023moleculesN2

Divide these two numbers to get

3.011⋅102310.5385⋅1023=27→

the molecule ratio is equal to the mole ratio

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Answer 2

Answer:

the ratio of molecule will be = 2:7