who is physics genius solve this ...two tuning fork when sounded simultaneously give on beat each 0.4s what is difference in frequnices
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2.5 will be difference in freq.
Vishakadvani:
give me solution
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t=1/[2(n1-n2)]
0.4=1/2(n1-n2)
0.8=1/(n1-n2)
n1-n2=1/0.8
n1-n2=1.25sec.
hope the answer is helpful.
0.4=1/2(n1-n2)
0.8=1/(n1-n2)
n1-n2=1/0.8
n1-n2=1.25sec.
hope the answer is helpful.
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