Who is talented....?
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Let the tension on the string is T
And acceleration of mass m is a
F b d for mass m ( ring)
Tcos 60 =ma
T =2ma
Fbd for mass m/2 ( mass q)
m/2g - T =m/2 a cos 60
M/2 g - 2ma =ma/2cos 60
g/2 - 2a = a /4
2a + a/4 = g/2
9/4 a =g/2
a = 9/2 g
Load fbd diagram in the morning
And acceleration of mass m is a
F b d for mass m ( ring)
Tcos 60 =ma
T =2ma
Fbd for mass m/2 ( mass q)
m/2g - T =m/2 a cos 60
M/2 g - 2ma =ma/2cos 60
g/2 - 2a = a /4
2a + a/4 = g/2
9/4 a =g/2
a = 9/2 g
Load fbd diagram in the morning
rishi7586:
sorry for late reply
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