who know only they will give answer and don't know don't give mischievous answer or bad answer.Thank you. question 11 and 12
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To find the zeroes of polynomial then equation is equal to zero so,
11)
1) p(x) = 0
x-4 = 0
x = 4
2) g(x) = 0
3-6x = 0
-6x = -3
x = -3/-6
x = 1/2
3) q(x) = 0
2x - 7 = 0
2x = 7
x = 7/2
4) h(y) = 0
2y = 0
y = 0/2
y = 0
12)
p(x) = 0
(x-2)²-(x+2)² = 0
(x)²+(2)²-2(x)(2) - ( (x)²+(2)²+2(x)(2) ) = 0
x²+4-4x -(x²+4+4x) = 0
x²+4-4x-x²-4-4x = 0
-4x-4x = 0
-8x = 0
x = 0/-8
x = 0
11)
1) p(x) = 0
x-4 = 0
x = 4
2) g(x) = 0
3-6x = 0
-6x = -3
x = -3/-6
x = 1/2
3) q(x) = 0
2x - 7 = 0
2x = 7
x = 7/2
4) h(y) = 0
2y = 0
y = 0/2
y = 0
12)
p(x) = 0
(x-2)²-(x+2)² = 0
(x)²+(2)²-2(x)(2) - ( (x)²+(2)²+2(x)(2) ) = 0
x²+4-4x -(x²+4+4x) = 0
x²+4-4x-x²-4-4x = 0
-4x-4x = 0
-8x = 0
x = 0/-8
x = 0
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