Question

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Answer 1

Answer:

Cross-multiply to get:

t = 3 s(2 t-s)

t = 6 st - 3 s^2

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6 st-t = 3 s^2

t(6 s-1) = 3 s^2

t = (3 s^2)/(6 s-1)

Answer 2

Answer :

Given :

• $\dfrac{t}{2t-s}$ = 3s
• The value of s = 3

Find :

• The value of t.

Solution :

As we have the value of s = 3 from question, put into the equation given,

That is ,

= $\dfrac{t}{2t-s}$ = 3s

= $\dfrac{t}{2t-3}$ = 3×3

= t= 9(2t+3)

= t = 18t + 27

= t - 18t = 27

= 17t = 27

= t = $\dfrac{27}{17}$

The answer is 17/27 is the required answer.

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