who many bit strings of length 7 are there?
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Answer:
The bit strings of length 7 have 64.
Step-by-step explanation:
If a string carries k 1’s then there could be 7-k 0’s could be there.
the quantity of strings with k 1’s and 7-k 0’s is 7!/(k!)(7-k)!
the maximum value of k is 3.
if we expect the minimum value of k is 0, then we've got the full quantity of strings is
= (7!/0!7!) +(7!/1!6!)+(7!/2!5!)+(7!/3!4!)
=1+7 +21+35
=64
if we expect the minimum value of k is 1, then the quantity of strings is = =7+21+35
=63.
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