Question

who to solve it tell​

Answer 1

Answer:

√3

1 -

3

Step-by-step explanation:

pero nd ko ung kung tama

Answer 2

$\sin(30)^{o} = \frac{1}{2} \\ \sin(60)^{o} = \frac{ \sqrt{3} }{2}$

$LHS = \frac{ \sin(30)^{o} + sin(60)^{o}}{1 + sin(30)^{o} + sin(60)^{o}} \\ LHS = \frac{ \frac{1}{2} + \frac{ \sqrt{3} }{2} }{1 + \frac{1}{2} + \frac{ \sqrt{3} }{2} } \\ LHS = \frac{ \frac{ \sqrt{3 + 1} }{2} }{ \frac{2 + 1 + \sqrt{3} }{2} } \\ LHS = \frac{ \sqrt{3} + 1 }{3 + \sqrt{3} } \\ LHS = \frac{ \sqrt{3} + 1 }{3 + \sqrt{3} } \times \frac{3 - \sqrt{3} }{3 - \sqrt{3} } \\ LHS = \frac{3 \sqrt{3} - ( \sqrt{3})^{2} + 3 - \sqrt{3} }{(3)^{2} - {( \sqrt{3}) }^{2} } \\ LHS = \frac{3 \sqrt{3} - 3 + 3 - \sqrt{3} }{9 - 3} \\ LHS = \frac{2 \sqrt{3} }{6} \\ LHS = \frac{ \sqrt{3} }{3} \\ therefore \: LHS =RHS.$

$hope \: it \: helps \: you: )$