who want ☆50 points☆
Answers
2.Let x = 0.7Bar
⇒ x = 0.777.....(1)
Multiplying (equation 1) by 10
⇒ 10x = 7.7..... = 7.777 ......(2)
Subtracting (1) from (2)
⇒ 10x - x = 9x
⇒ 7.777 - 0.777 = 7
⇒ 9x = 7
⇒ x = 7/9
Let y = 0.47Bar
⇒ y = 0.4747 .............. ........(1)
Multiplying (equation 1) by 100
⇒ 100y = 47.4747 ............(2)
Subtracting (eqn 1) from (eqn 2)
=> 100y - y = 99y
=>47.4747 - 0.4747 = 47
=>99y = 47
=>y = 47/99
Now,
0.7Bar = 7/9
and 0.47Bar = 47/99
0.6 = 6/10
6/10 + 7/9 + 47/99
Taking L.C.M. of the denominator and then solving it, we get.
⇒ (594 + 770 + 470)/990
⇒ 1834/990
⇒ 917/4959
hey mate here is ur answer..
☮️
2.Let x = 0.7Bar
⇒ x = 0.777...(1)
Multiplying (equation 1) by 10
⇒ 10x = 7.7.. = 7.777 ...(2)
Subtracting (1) from (2)
⇒ 10x - x = 9x
⇒ 7.777 - 0.777 = 7
⇒ 9x = 7
⇒ x = 7/9
Let y = 0.47Bar
..(1)
Multiplying (equation 1) by 100
⇒ 100y = 47.4747.(2)
Subtracting (eqn 1) from (eqn 2)
=> 100y - y = 99y
=>47.4747 - 0.4747 = 47
=>99y = 47
=>y = 47/99
now, ,
0.7Bar = 7/9
and 0.47Bar = 47/99
0.6 = 6/10
6/10 + 7/9 + 47/99
Taking L.C.M. of the denominator and then solving it, we get.
⇒ (594 + 770 + 470)/990
⇒ 1834/990
⇒ 917/4959
♓hopes its helps you..
answered by, advanced mod