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Answers
Answer:
Let the first angle =ZA =x
the second angle = zB = 1/3x and the third angle = 2C = x + 26°
ZA+ 2B + 2C = 180°
X+ 1/3x+x+26° = 180° 7x/3 + 26° = 180°
7x/3 = 180° -26°
7x/3 = 154°
x = 154° x 3/7
x = 66°
<A = x= 66°
4B 1/3 x = 1/3 x 66° = 22°
<C = x + 26° = 66°+ 26° = 92°
Answer:
66°, 22° and 92°
Step-by-step explanation:
assume the three angles as x,y,z.
given conditions:
second angle is one third of first one ===> y = x/3. --1
third angle is 26 degrees more than first one ===> z = X+26. --2
Formula:
sum of all the angles in a triangle = 180°
X+y+z = 180°
substitute equation 1 and 2 in above formula.
x+ x/3 + x+ 26 =180
2x+X/3 = 154
7x/3 = 154
x = 154 * 3/7
x = 22 * 3 = 66
so, first angle X = 66°
substitute above value in equation 1 and 2
y = 66/3 = 22°
z = 66+26 = 92°
so three angles are 66°, 22° and 92°