Math, asked by juanjuel27, 30 days ago

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Answered by heenasane03
1

Answer:

Let the first angle =ZA =x

the second angle = zB = 1/3x and the third angle = 2C = x + 26°

ZA+ 2B + 2C = 180°

X+ 1/3x+x+26° = 180° 7x/3 + 26° = 180°

7x/3 = 180° -26°

7x/3 = 154°

x = 154° x 3/7

x = 66°

<A = x= 66°

4B 1/3 x = 1/3 x 66° = 22°

<C = x + 26° = 66°+ 26° = 92°

Answered by prudhvinadh
0

Answer:

66°, 22° and 92°

Step-by-step explanation:

assume the three angles as x,y,z.

given conditions:

second angle is one third of first one ===> y = x/3. --1

third angle is 26 degrees more than first one ===> z = X+26. --2

Formula:

sum of all the angles in a triangle = 180°

X+y+z = 180°

substitute equation 1 and 2 in above formula.

x+ x/3 + x+ 26 =180

2x+X/3 = 154

7x/3 = 154

x = 154 * 3/7

x = 22 * 3 = 66

so, first angle X = 66°

substitute above value in equation 1 and 2

y = 66/3 = 22°

z = 66+26 = 92°

so three angles are 66°, 22° and 92°

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