History, asked by manjubora6499, 1 year ago

Who was William Jennings Bryan? A. the first People’s Party candidate for president B. the Democratic candidate for president in 1896 C. the first leader of the Knights of Labor organization D. the candidate who defeated James B. Weaver in 1892

Answers

Answered by jen4203
7
he was the democratic candidate for president in 1896.
°°°Here is some of his basic information:
William Jennings Bryan was an American orator and politician from Nebraska. Beginning in 1896, he emerged as a dominant force in the Democratic Party, standing three times as the party's nominee for President of the United States.

Born: 19 March 1860, Salem, Illinois, United States

Died: 26 July 1925, Dayton, Tennessee, United States

President: Woodrow Wilson

Speech: Cross of Gold speech
William Jennings Bryan was an American orator and politician from Nebraska. Beginning in 1896, he emerged as a dominant force in the Democratic Party, standing three times as the party's nominee for President of the United States. Wikipedia

Born: 19 March 1860, Salem, Illinois, United States

Died: 26 July 1925, Dayton, Tennessee, United States

President: Woodrow Wilson

Speech: Cross of Gold speech

Political party: Democratic Party

Attachments:
Answered by vijayhalder031
0

Concept introduction:

Former Nebraskan representative William Jennings Bryan gave the Cross of Gold address on July 9, 1896, at the Democratic National Convention in Chicago. Bryan advocated for "free silver" or bimetallism in his speech because he thought it would benefit the country economically.

Explanation:

Given that,

We have to find, who was William Jennings Bryan.

According to the question,

American lawyer, orator, and politician William Jennings Bryan lived from March 19, 1860, to July 26, 1925. He began to take center stage in the Democratic Party in 1896, and he went on to serve as the party's nominee for president three times—in 1896, 1900 and 1908.

Final Answer:

B. the Democratic candidate for president in 1896.

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