who we draw resistor in this question?
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Explanation:
( a) first we connect two resistance in parallel,then its equivalent resistance became
3 i. e,
Re = 1/ (1/6 + 1/6)
Re = 1/ (1/3)
Re = 3Ω
and then connect them in series combination
then Re = 3+ 6 = 9Ω
( b) In this case first we connect two resistance in series then Re = 12Ω and connect them in parallel combination then equivalent resistance became 4Ω
i. e, Re = 1/(1/12 + 1/6)
Re = 1/(1/4)
Re = 4Ω
I HOPE THIS MAY HELP YOU
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