Question

who will ans the 2 questions in in the pic​

Answer 1

$\large\green{\textsf{✩ Verified Answer ✓ }}$

Question no 1 :-

Let sum be p and

A= p(1+r/100)n

=p(1+5/100)2

=p(21/20)2

=441/400p

CI= A-P

= 441/400p-p

= 41/400p

Therefore CI= 512.50(given)

= CI=41/400p(Proved)

= 41/400p= 512.50

=p= 512.50*400/41

= p=4200rs

Question no 2 :-

answer in the attachment.

$\bf\pink{\textsf{Answered By MrPaglu}}$

Answer 2

Answers :-

Question no 1 :-

Let sum be p and

A= p(1+r/100)n

=p(1+5/100)2

=p(21/20)2

=441/400p

CI= A-P

= 441/400p-p

= 41/400p

Therefore CI= 512.50(given)

= CI=41/400p(Proved)

= 41/400p= 512.50

=p= 512.50*400/41

= p=4200rs

Question no 2 :-

answer in the attachment.