Math, asked by madhuram415, 13 days ago

who will answer Brainlist​

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Answered by WildCat7083
3

 \sf \: LHS= \frac{ \sin(o) -  \cos(o)  }{ \sin(o) +  \cos(o)  }  + \frac{ \sin(o)  +  \cos(o)  }{ \sin(o)  -   \cos(o)  }  \\  \\  \sf \:  \frac{( \sin(o)  -  \cos(o) ) {}^{2}  +(  \sin(o)  -  \cos(o)) {}^{2}  }{( \sin(o) +  \cos(o) )(\sin(o)  -  \cos(o) ) }  \\  \\  \sf \:  \frac{ \sin {}^{2} (o) +  \cos {}^{2} (o)   - 2 \sin(o)  \cos(o)  +  \sin {}^{2} (o) \cos {}^{2} (o) + 2 \sin(o)  \cos(o)}{ \sin {}^{2} (o)  -  \cos(o) }  \\  \\  \sf \: as \: we \: know \: that \\  \sf \: { \red{ { \sin }^{2}  +  { \cos }^{2}  = 1}} \\  \sf{ {1 -  \cos {}^{2}  =  \sin {}^{2} }} \\  \sf{ { { \cos }^{2}  = 1 -  { \sin}^{2} }} \\  \sf{ { \cos {}^{2}  =  { \sin}^{2}  - 1}} \\   \\  \sf \:  \frac{1 + 1}{ \sin {}^{2} (o) +  {  \sin {}^{2} (o)  } } \\  \\  \sf \:  \frac{2}{2 \sin {}^{2} (o)  - 1}  \\  \\

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 \sf \: @WildCat7083

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