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(a+b)3
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Step-by-step explanation:
(a + b)³
=> [(a + b)(a + b)](a + b)
=> [a(a + b) + b(a + b)] (a + b)
=> (a² + ab + ab + b²) (a + b)
=> a ( a² + 2ab + b²) + b(a² + 2ab + b²)
=> a³ + 2a²b + ab² + a²b + 2ab² + b³
=> a³ + 3a²b + 3ab² + b³
=> a³ + b³ + 3a²b + 3ab²
=> a³ + b³ + 3ab( a + b)
Therefore,
(a + b)³ = a³ + b³ + 3ab(a + b)
Hope it helps!
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