Question

who will answer first they will be marked as brainiest answer ​

Answer 1

Step-by-step explanation:

first we will rationalise all the three terms...

√6/√2+√3

=√6/√2+√3*√2-√3/√2-√3

=√12-√18/(√2)²-(√3)²

=√12-√18/-1

=-(√12-√18)

=-√12+√18

3√2/√6+√3

=3√2/√6+√3*√6-√3/√6-√3

=3√12-3√6/(√6)²-(√3)²

=3√12-3√6/3

=3(√12-√6)/3

=√12-√6

4√3/√6+√2

=4√3/√6+√2*√6-√2/√6-√2

=4√18-4√6/(√6)²-(√2)²

=4(√18-√6)/4

=√18-√6

now substitute the values ..

-√12+√18+√12-√6 / √18-√6

=√18-√6/√18-√6

=1

hope this helps you ...

plz mark me as brainlist answer...