Question

who will answer he will brainliest
answer fast points please give a long answer note recipe answer with method I want​

Answer 1

Answer:

The bond dipole moment uses the idea of electric dipole moment to measure the polarity of a chemical bond within a molecule. It occurs whenever there is a separation of positive and negative charges. The bond dipole μ is given by: \mu =\delta

Answer 2

Answer:

$\frac{25 \times {t}^{ - 4} }{ {5}^{ - 3} \times 10 \times {t}^{ - 8} } = \frac{ {5}^{4} \times {t}^{4} }{2}$

Step-by-step explanation:

$\frac{25 \times {t}^{ - 4} }{ {5}^{ - 3} \times 10 \times {t}^{ - 8} } \\ = \frac{25 \times { (\frac{1}{t}) }^{4}}{ {( \frac{1}{5}) }^{3} \times 10 \times { (\frac{1}{t} )}^{8} } \\ = \frac{25 \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t}}{ \frac{1}{5} \times \frac{1}{5} \times \frac{1}{5} \times 10 \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} } \\ = 25 \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} \times \frac{1}{t} \times 5 \times 5 \times 5 \times \frac{1}{10} \times t \times t \times t \times t \times t \times t \times t \times t \\ = \frac{5 \times 5 \times 5 \times 5 \times t \times t \times t \times t}{2} \\ = \frac{ {5}^{4} \times {t}^{4} }{2}$