Question

who will answer this question they select as brand list and 25 points

Answer 1

hiii

here is the answer

Since, AOB is the diameter,

∠ACB = 90o (angles in a semi-circle is a right angle)

ΔABC is an isosceles triangle [AB = BC(Given)]

∴ ∠CAB = ∠ABC (isosceles triangle property)

but, ∠CAB + ∠ABC + ∠ACB = 180o (angle sum property of a triangle)

∠CAB + ∠ABC + 90o = 180o [∠ACB = 90o(proved)]

2∠CAB +  90o = 180o [∠CAB = ∠ABC (proved)]

2∠CAB = 180o - 90o = 90o

∠CAB  = 90o/2 = 45o 

∠CAB = 45o 

hope helped

Answer 2

Answer: ∠CAB = 45°

Here, AOB is the diameter,

∠ACB = 90° (angles in a semi-circle is a right angle)

ΔABC is an isosceles triangle [AB = BC(Given)]

∴ ∠CAB = ∠ABC (isosceles triangle property)

but, ∠CAB + ∠ABC + ∠ACB = 180° (angle sum property of a triangle)

∠CAB + ∠ABC + 90o = 180o [∠ACB = 90° (proved)]

2∠CAB +  90° = 180°

 [∠CAB = ∠ABC (proved)]

2∠CAB = 180° - 90° = 90°

∠CAB  = 90°/2 = 45°

∠CAB = 45° _____(Ans.)

Thanks!