Who will put correct answers I will mark as brainliest
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we know that, 140°+angle A+angle C=180°
=angle A +angle C=180°-140°
=angle A + angle C =40°
And angle x is the external angle of ∆ABC
so, angle X = angle A +angle C
angle X =40°
hence the answer
Answered by
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We know that sum of opposite angles in a cyclic quadrilateral is 180°
∠ADC + ∠ABC = 180°
=>∠ABC= 180°-140°= 40°
=>∠ABC= 40°
since ∠ACB is an angle in a semi circle so
∠ACB = 90°
In ∆ABC,
∠ABC+∠CAB+∠ACB=180°
=> 40°+X°+90°=180°
=> 130°+X° = 180°
=> X°= 180°-130° = 50°
Therefore Value of X = 50°
Hope it helps ✌️
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