who will solve will mark as brainly
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Given : XA ⊥ YA & YB ⊥ XB
XA = YB
To prove : ∆AXY ≅ ∆BYX
Proof : In ∆AXY & ∆BYX,
XY = XY (common side)
∠XAY = ∠YBX = 90° ( XA⊥YA,YB⊥XB)
XA = YB (given)
∴ ∆AXY ≅ ∆BYX by SAS condition
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