Question

WHO WILL TELL THE ANSWER I WILL MARK HIM AS A BRAINLIST​

Answer 1

Answer:

1-d,2-b,3-a,4-c

Step-by-step explanation:

1) a5=-9

   a+4d=-9 ⇒⇒⇒⇒⇒⇒⇒eq 1

       a9=7

        a+8d=7⇒⇒⇒⇒⇒⇒⇒eq 2

           

Solving, equation 1 and 2

d = 4

a = -25

Finding a14

    a+13d=-25+52=27

So, a14(14th term) is 27

4)First two digit number divisible by 3 = 12  

Last two digit number divisible by 3 = 99  

An arithmetic progression (A.P) is a progression in which the difference between two consecutive terms is constant.  

A.P = 12,15,18,…,99  

here  

First term (a) = 12

Common difference (d) = 3

Let us consider there are n numbers then

an = 99

a + (n – 1)d = 99

12 + (n – 1)3 = 99  

12 + 3n – 3 = 99

n = 29+1

n = 30

∴ Two digit numbers divisible by 3 = 30.

3)a10=44                      

   a+9d=44 ⇒⇒⇒⇒⇒⇒eq1                

      a15=64

        a+14d=64⇒⇒⇒⇒⇒eq 2

solving eq 1 and 2 then a=8

hope this will helpfull to you