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Q: E and F are points on the sides PQ and PR respectively of a ΔPQR. For which of the following cases, EF || QR is
PE = 2 cm, EQ= 3 cm, PF = 4 cm and FR = 9 cm
None of these
PE = 5 cm, EQ= 15 cm, PF = 4 cm and FR = 12 cm
PE = 3 cm, EQ= 2 cm, PF = 6 cm and FR = 8 cm
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Answer: In ΔPQR, E and F are two points on side PQ and PR respectively. Hence, EF is not parallel to QR. Hence, EF is parallel to QR.
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