Math, asked by JomiaThomas, 9 months ago

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Answered by trendyboy
30

Step-by-step explanation:

This can be the equation for concident= 6x- 10y =22

This can be for intersecting= 9x - 15y =11

This can be for parallel=6x -23y =22

Answered by DrNykterstein
75

Given, Linear equation 3x - 5y = 1

We need to find another linear equation in two variable such that the geometrical representation of linear pair is :

Intersecting lines :-

We know the standard form of linear equation, ax + by = c

Comparing the given linear equation with the standard form, we get

  • a₁ = 3
  • b₁ = -5
  • c₁ = 1

Another linear equation : a₂x + b₂y = c₂

For Intersecting lines , there should be a unique solution. so for unique solution, following condition should be true.

a₁ / a b₁ / b₂

⇒ 3 / a₂ ≠ -5 / b₂

⇒ a₂ / b₂ ≠ 3 / -5

Hence, Another linear equation would be:

4x - 6y = 1

Coincident lines :-

Comparing the given linear equation with the standard form of linear equation in two variable, we get

  • a₁ = 3
  • b₁ = -5
  • c₁ = 1

Another linear equation : a₂x + b₂y = c₂

Following condition evaluates true when the geometrical representation of two linear equations are coincidence.

a₁ / a₂ = b₁ / b₂ = c₁ / c₂

Multiply the given equation by 2 to get a linear equation that will have infinite common solutions with the given equation.

6x - 10y = 2

Parallel lines :-

After comparing the given linear equation with the standard form of linear equation in two variable, we get

  • a₁ = 3
  • b₁ = -5
  • c₁ = 1

Another linear equation : a₂x + b₂y = c₂

We need to find the values of a₂ , b₂ & c₂ such that the given condition comes to true.

a₁ / a₂ = b₁ / b₂ c₁ / c₂

Another linear equation:

3x - 5y = 2

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