Question

Whoever answers correct I will follow and like

Answer 1

Answer:

$\huge\mathtt\purple{SOLUTION:-}$

$\mathtt{f(x) = 5x - {4x}^{2} + 3}$

Substitute the value of x which is (-1)

$\mathtt{f( - 1) = 5 \times ( - 1) - {4 \times ( - 1)}^{2} + 3}$

$\mathtt{ = ( - 5) - 4 + 3}$

$\mathtt{ = ( - 5) - 1}$

$\mathtt{ = - 6}$

$\fbox\purple{Option 1 is correct}$

Now solve 2 Ques

$\mathtt{x + 1 = 0}$

$\mathtt{x = ( - 1)}$

Substitute the value of x which is (-1)

$\mathtt{ {x}^{3} + {x}^{2} + x + k }$

=(-1)+1 -1+k = 0

= -1 + k = 0

$\mathtt{k = ( 1)}$