Question

whoever answers this question i will mark him as the brainliest
100%sure

Answer 1

Hey user

Here is your answer :-

Given :-
ABCD is a rectangle

To prove :-
∆ABE ~= ∆ CDF

Proof :-

1. In ∆ ABE , /_ AEB = 90°. ... Given

2. In ∆ CDF . /_CFD = 90°. ... Given

3. ∆ ABE & ∆ CDF are right angled triangles

4.Side AB ~= Side CD ... sides of rectangle

5. In ∆ ABE & ∆ CDF

( i ) /_ AEB ~= /_ CFD. ...From 1 & 2 .

( ii ) hypo. AB ~= hypo. CD. ... From 3.

6. Hence ∆ABE ~= ∆ CDF. ...Hypo side test

Thank you.