Math, asked by riyaswaroop, 1 year ago

Whoever will solve this question I will mark them as the brainliest.....


Please help me with this question guys....

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Answers

Answered by Sanskriti141
46
ANSWER
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√12 + √27 + √108 + √75 + √147

=> √12 = √2 × √2 × √3 = 2√3 -------- 1

=> √27 = √3 × √3 × √3 = 3√3 -------- 2

=> √108 = √6 × √6 ×√3 = 6√3 --------- 3

=> √75 = √5 × √5 × √3 = 5√3 --------- 4

=>√147 = √7 × √7 × √3 = 7√3 --------- 5

Adding 1 , 2 , 3 , 4 and 5 , we get

=> 2√3 + 3√3 + 6√3 + 5√3 + 7√3

{ Taking common √3 }

=> √3 ( 2 + 3 + 6 + 5 + 7 )

=> √3 ( 23 )

=> 23√3 ANS

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Anonymous: Well explained
CBSEMP: superb explained
nethranithu: well explained ans sis
Sanskriti141: thanks everyone
Anonymous: correctly explained
Sanskriti141: tysm
CBSEMP: nice explained Xd
Anonymous: Splendid answer Behena :-)
Answered by dfgh4
10
 = > \sqrt{12} + \sqrt{27} + \sqrt{108} + \sqrt{75} + \sqrt{147} \\ \\ = > 2 \sqrt{3} + 3 \sqrt{3} + 6 \sqrt{3} + 5 \sqrt{3} + 7 \sqrt{3} \\ \\ = > 5 \sqrt{3} + 11 \sqrt{3} + 7 \sqrt{3} \\ \\ = > 16 \sqrt{3} + 7 \sqrt{3} \\ \\ = > 23 \sqrt{3} \\ \\ hope \: \: its \: help

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dfgh4: thanx dear
dfgh4: wlcm dear
dfgh4: thnx
Anonymous: Good answer
dfgh4: thanx
dfgh4: so i don't care
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