Math, asked by anucshree, 2 months ago

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Answers

Answered by Anonymous
3

Given

Height of building = 60m

The angle of depression of top and bottom of a tower is 45⁰ and 60⁰

To Find

The Height of tower

Let

Distance between building and tower is AB

Height of tower be x

Height of Building BC = 60

Now Take , △ABC

Tan60⁰ = BC/AB

:- Where Tan60⁰ = √3

√3 = 60/AB

AB = 60/√3

AB = 60/√3 × √3/√3

AB = 20√3m

Now Take △DEC

Tan45⁰ = EC/DE

We know that AB = EC , where AB = 20√3 and tan45⁰=1

1 = x/20√3

x = 20√3

Now height of tower is 60-x , so

BE = 60-x

BE = 60 - 20√3

:- √3 = 1.732

BE = 60 - 20×1.732

BE = 60 - 34.64

BE = 25.36 m

Answer

Height of Tower is 25.6m

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Answered by TheBestWriter
1

Given

Height of building = 60m

The angle of depression of top and bottom of a tower is 45⁰ and 60⁰

To Find

The Height of tower

Let

Distance between building and tower is AB

Height of tower be x

Height of Building BC = 60

Now Take , △ABC

Tan60⁰ = BC/AB

:- Where Tan60⁰ = √3

√3 = 60/AB

AB = 60/√3

AB = 60/√3 × √3/√3

AB = 20√3m

Now Take △DEC

Tan45⁰ = EC/DE

We know that AB = EC , where AB = 20√3 and tan45⁰=1

1 = x/20√3

x = 20√3

Now height of tower is 60-x , so

BE = 60-x

BE = 60 - 20√3

:- √3 = 1.732

BE = 60 - 20×1.732

BE = 60 - 34.64

BE = 25.36 m

Answer

Height of Tower is 25.6m

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