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Answers
Given
Height of building = 60m
The angle of depression of top and bottom of a tower is 45⁰ and 60⁰
To Find
The Height of tower
Let
Distance between building and tower is AB
Height of tower be x
Height of Building BC = 60
Now Take , △ABC
Tan60⁰ = BC/AB
:- Where Tan60⁰ = √3
√3 = 60/AB
AB = 60/√3
AB = 60/√3 × √3/√3
AB = 20√3m
Now Take △DEC
Tan45⁰ = EC/DE
We know that AB = EC , where AB = 20√3 and tan45⁰=1
1 = x/20√3
x = 20√3
Now height of tower is 60-x , so
BE = 60-x
BE = 60 - 20√3
:- √3 = 1.732
BE = 60 - 20×1.732
BE = 60 - 34.64
BE = 25.36 m
Answer
Height of Tower is 25.6m
Given
Height of building = 60m
The angle of depression of top and bottom of a tower is 45⁰ and 60⁰
To Find
The Height of tower
Let
Distance between building and tower is AB
Height of tower be x
Height of Building BC = 60
Now Take , △ABC
Tan60⁰ = BC/AB
:- Where Tan60⁰ = √3
√3 = 60/AB
AB = 60/√3
AB = 60/√3 × √3/√3
AB = 20√3m
Now Take △DEC
Tan45⁰ = EC/DE
We know that AB = EC , where AB = 20√3 and tan45⁰=1
1 = x/20√3
x = 20√3
Now height of tower is 60-x , so
BE = 60-x
BE = 60 - 20√3
:- √3 = 1.732
BE = 60 - 20×1.732
BE = 60 - 34.64
BE = 25.36 m
Answer
Height of Tower is 25.6m