Math, asked by leothakur6165, 6 days ago

Whole procedure of prime factorisation of LCM of the numbers 24,28,196

Answers

Answered by Anonymous
0

Answer:

1176

Step-by-step explanation:

Prime factorization of the given numbers are  

24=2×2×2×3  

28=2×2×7  

196=2×2×7×7  

Notice that 2 occurs as a prime number factor maximum 3 times , 3 one times , 7 two times  

∴ L.C.M =2×2×2×3×7×7=1176

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Answered by sahuchetan333
0

Answer:

Prime factorization of the given numbers are 

24=2×2×2×3 

28=2×2×7 

196=2×2×7×7 

Notice that 2 occurs as a prime number factor maximum 3 times , 3 one times , 7 two times 

∴ L.C.M =2×2×2×3×7×7=1176 

Step-by-step explanation:

Prime factorization of the given numbers are 

24=2×2×2×3 

28=2×2×7 

196=2×2×7×7 

Notice that 2 occurs as a prime number factor maximum 3 times , 3 one times , 7 two times 

∴ L.C.M =2×2×2×3×7×7=1176 

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