Question

Whole root 1+ sin theta ÷1-sintheta +whole root 1-sintheta ÷ 1+sintheta= 2sectheta?

Answer 1

Answer:

Step-by-step explanation:

LHS=1+sinθ1−sinθ−−−−−√+1−sinθ1+sinθ−−−−−√=1+sinθ+1−sinθ(1−sinθ)(1−sinθ)√=21−sin2θ√=2cosθ=2secθ=RHSHence, proved.