Math, asked by etibrihaspati06, 8 months ago

Whole root 2 + root3 + whole root2-root3

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Answers

Answered by Anonymous
21

 \huge  \bf{Question}

▶Whole root 2 + root 3 + whole root2-root3

 \huge \bf{Solution}

▶X =(√3+√2)/(√3-√2)

By taking conjugate, we get

X  = (√3+√2) (√3+√2) /(√3-√2) (√3+√2)

    =(√3+√2)²/(√3²-√2²)

    =3+2√6+2 / (3-2) = 5+2√6

Y   = (√3-√2)/(√3+√2)

By taking conjugate we get

Y    = (√3-√2)²/ (√3+√2)(√3-√2)

      = 3-2√6+2/√3²-√2²

       = 5-2√6/(3-2) = 5-2√6

X²     = (5+2√6)² = 25+20√6+24 =

49+20√6

Y²      = (5-2√6)² = 25-20√6+24  =

49-20√6

X²+Y² =  49+20√6+49-20√6

 \huge\ {x {}^{2}  + y {}^{2}  = 98}

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