Question

whole root 5+2√6-1/-5+2√6










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केका​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

Answer 2

Answer:

To find square root of surds,in this case you should make it in form of a^2+b^2+2ab

Here:

5+2√(6)

=√(2)^2+√(3)^2+2√(2)√(3)

=[√(2)+√(3)]^2

now square root of 5+2√(6)is

√{[√(2)+√(3)]^2}

=√(2)+√(3)

SO answer is √(2)+√(3)